India cricket team were bowled out for their lowest-ever One Day International (ODI) total in New Zealand (92) after Trent Boult ran through their batting order in the ongoing fourth ODI on Thursday at the Seddon Park in Hamilton.

When they were reeling at 35 for 6 after just 13.1 overs, India were in danger of succumbing to their lowest-ever ODI total (54 vs Sri Lanka in 2000). However, a handy cameo from all-rounder Hardik Pandya and a 25-run stand between Kuldeep Yadav and Yuzvendra Chahal helped India save the blushes.

Skipper Virat Kohli is not a part of the team for the final two ODIs and the three Twenty-20 games as BCCI has

decided to rest him ahead of the home series against Australia. In Kohli's absence, Rohit Sharma is captaining the Men in Blue. Rohit is also making his 200th ODI appearance today.

Trent Boult was the wrecker-in-chief as the left-arm pacer was getting the ball to swing both ways so much so that captain Kane Williamson let him bowl his quota of 10 overs in one go.

Team India has already clinched the series with victories in the first three games. A win today and a four-nil lead will be India's biggest series victory across all formats in their 52 years of touring New Zealand.

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